Question
The distance at which the magnetic field on axis as compared to the mag. field at the centre of the coil carrying current I and radius $R$ is (1/8), would be(a) $R$(b) $\sqrt{2} \mathrm{R}$(c) $2 \mathrm{R}$(d) $\sqrt{3} \mathrm{R}$
Step 1
Step 1: The magnetic field at a distance x from the center of the coil on its axis is given by the formula: \[B_x = \frac{\mu_0 I R^2}{2(x^2 + R^2)^{3/2}}\] Show more…
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