00:01
In this exercise, we are told that x is exponentially distributed with a mean of 5 miles.
00:07
That is, the distance between cracks in a highway is exponentially distributed with a mean of 5 miles.
00:15
For part a, we are asked for the probability that there are no cracks in a 10 -mile stretch of highway.
00:22
That is the same as the probability that we go at least 10 miles before encountering a crack, which is the probability that x is greater than 10.
00:31
Is equal to 1 minus the cdf of x, evaluated at 10.
00:44
The cdf of an exponential random variable is given by this formula, and lambda is equal to 1 over the mean.
01:09
So this comes out to e to the negative 0 .2 times 10, and that gives us a probability of 0 .1353.
01:26
For part b, we are asked for the probability that there are two major cracks in a 10 -mile stretch of highway.
01:34
If the distance between cracks is exponentially distributed, then the number of cracks in a given distance is a poisson process.
01:44
And so we can say what is the probability that the number of cracks is equal to 2.
01:51
This is where x is equal to 10 miles.
01:59
This is equal to e to the minus lambda x times lambda x to the exponent n over n factorial.
02:17
Gives us e to the minus 2 times 2 squared over 2 factorial.
02:27
And this comes out to 0 .2707.
02:32
That's the probability of 2 cracks in length of 10 miles.
02:41
Part c asked for the standard deviation of the distance between cracks.
02:47
For an exponential random variable, the standard deviation is equal to 1 over lambda, or it's equal to the mean, which we know is 5 miles...