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The distance between the eyepiece and the objective lens in a certain compound microscope is 20.0 $\mathrm{cm} .$ The focal length of the objective is $0.500 \mathrm{cm},$ and that of the eyepiece is 1.70 $\mathrm{cm} .$ Find the overall magnification of the microscope.

2.14 \mathrm{cm}

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So we have the distance between the objective and the I piss, which is also the length of the microscope is 20 centimeter. The focal length of the objective is 0.5 centimeter, and the focal length of the eyepiece is 1.7. Senator. Now, to find the overall magnification of the microscope, we know that m the overall magnification m is the lateral magnification of the objective times angular magnification of the ivy's right. And this is also L over f o times 25 centimeter over focal length of the I piss. So that means for all of this we have here, um, is going to be cool too negative of 20 over 0.5 times 25 over 1.7. So this is going to give me a negative 588. That is the overall magnification of the microscope.

University of Wisconsin - Milwaukee