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The distribution of molecular velocities in a sample of helium is shown in Figure 9.34. If the sample iscooled, will the distribution of velocities look more like that of $\mathrm{H}_{2}$ or of $\mathrm{H}_{2} \mathrm{O}$ ? Explain your answer.

After cooling, the distribution of molecular velocities in a sample of helium will look more like that of $\mathrm{H}_{2} \mathrm{O} .$ This is because decrease in temperature down He molecules causing them to behave as though they were heavier.

01:09

Aadit S.

Chemistry 101

Chapter 9

Gases

Rice University

Drexel University

University of Kentucky

Lectures

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that's what I'm going to be talking about. The root mean square velocity. So we have you root, Mean square equal to fruit bar You quiet. This is also equal to route. You squared one on you squared too on dso so on and so forth adding up to you squared and nice all divided by n So do you want you to And you three values represent a velocity of a particle and 123 and respectively So the mathematical expression representing the relation of the molecular speed or the root mean square velocity where the matter the particle and temperature is as followed. So you root mean square people to route three r t over em where r is the gas constant So you root mean square of particles of gas is constant temperature if it's inversely proportional to the mass of the molecules of the gas as you can see and this equation him so therefore the gasses that are made up of lighter molecules will have higher velocities. So after calling the distribution of the molecular velocities in a sample of helium will look more like H two up. So this is because of the decrease in temperature down helium molecules causes than to behavior, so they were heavier

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