00:01
So we have this rectangular slab and a ray of light is incident at the point a at an angle of 60 degrees.
00:12
And then we have to figure out whether it will emerge out of the block at that point a or not.
00:19
So part a, first thing we need to do is find the critical angle.
00:24
So theta c is equal to sine inverse of, so the refractive index of this material n is equal to 1 .523.
00:37
This is crown glass and the refractive index of air is equal to 1.
00:42
So that would be equal to the refractive index of air divided by n.
00:47
So that is equal to sine inverse of 1 over 1 .523, and that comes out to be equal to 41 .0 degrees.
00:58
Since 60 degrees, the angle of incidence is greater than theta critical, therefore total internal reflection will occur.
01:11
So this ray of light will actually go and strike this surface at point b.
01:16
Now, if this angle here, the angle of incidence is 60 degrees, then that means that the angle of incidence here would be 30 degrees.
01:27
And now since the angle of incidence now at b, at b we have theta incidence is less than the theta critical, therefore light will emerge out at point b.
01:50
So here the light will actually come out and there will be no total internal reflection...