00:01
Let us write the equation of speed of the transverse wave along a wire in terms of tension.
00:10
So let the speed be written as v.
00:13
So v can be equals to square root of tension or force divided by linear mass density or mass per unit length.
00:30
Now, squaring both sides, we can rewrite the above equation as force for the tension in the wire is equals to b squared multiplied by mass divided by lenn now now we can draw the free body diagram let us draw a free body diagram this is the inclined plane and let us draw the box here let this is the box on the inclined plane now let's put the these are the force direction.
01:24
These are the force direction.
01:27
In the upward direction the force will be perpendicular to this.
01:31
So this is the upper direction force.
01:40
Now in this direction the force will be m .g sine theta.
01:46
In this direction the force will be have.
01:51
In the upper direction the force will be normal force.
01:55
In lower direction the force will be mg post.
02:03
This is nothing but the angle theta.
02:04
Now let us solve the first part of the problem...