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The drawing shows a plane diving toward the ground and then climbing back upward. During each of these motions, the lift force $\overrightarrow{\mathbf{L}}$ acts perpendicular to the displacement $\overrightarrow{\mathbf{s}}$ , which has the same magnitude, $1.7 \times 10^{3} \mathrm{m},$ in each case. The engines of the plane exert a thrust $\overrightarrow{\mathbf{T}}$ , which points in the direction of the displacement and has the same magnitude during the dive and the climb. The weight $\overrightarrow{\mathbf{W}}$ of the plane has a magnitude of $5.9 \times 10^{4} \mathrm{N}$ . In both motions, net work is performed due to the combined action of the forces $\overrightarrow{\mathbf{L}}, \overrightarrow{\mathbf{T}},$ and $\overrightarrow{\mathbf{W}} .(a) Is more net work done during the dive or the climb? Explain. (b) Find the difference between the net work done during the dive and the climb.

a) More net work is done during the dive.b) $6.8 \times 10^{7} \mathrm{J}$

Physics 101 Mechanics

Chapter 6

Work and Energy

Work

Kinetic Energy

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So here we've given the situation where the plane is diving and then the plane is climbing and we are asked to find the network done in both cases and then to find the difference between the network during the dive. Andy climb. Now, the important numbers that we need to pay attention to is tthe e s, which is 1.7 times 10 to the power three and the, uh wait. Or the gravitational force, which is 5.9 times 10 to the power for will be using these values shortly. Now, let's so let's start by first finding the work done the network done during the dive. So when the plane is diving, there are three forces acting on it. There's the left. So we have worked on my left. There's the trust that we have worked on by the trust. And then there is also the work done by gravity. So those are the three forces doing work on the plane while it is in the dive worked on my left. Is your boss the left and displacement or perpendicular to each other? We do not know the trust force, so we cannot actually get a numerical value for the beauty. But what we can say is that the work and would become beauty. And then you can find the work done by the gravitational force, which would be equal to 5.9 times 10 to the power for That's the gravitation force. Times the displacement 1.7 times 10 to the power three meters and then times the course sign off 75 degrees, where 75 decreases the angle between the weight and the displacement. So we get the network. Done during the dive is W T plus 2.6 times 10 to the power seven jewels. Now let's calculate the work on during the climb. And again I have those three forces. So I would have worked on by the lift force worked on by the trust. Plus the work done by the force of gravity. Work done but left is still zero. I cannot still find the work done by trust, but it would be the same as during died because the same magnitude of tourists and the same displacement as well. So then let's calculate he worked on by gravity, which would be 5.9 times 10 to the power four times, 1.7 times 10 to the Power three. But the only thing that's going to change now is the angle between gravitational force and displacement, which now is 115 degrees. So we get W T minus 4.2 times 10 to the power seven jewels. And now, looking at these two values, we can definitely say that the work done during die is more than the work done during client. So that's the answer to part it. Now let's take a look at part B for Part B. We just have to find the difference. So since work died is Maur, so we'll say that's equal to work during Guy, minus the work during climb, and that difference is equal to 6.8 times 10 to the power seven jewels.

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