00:01
The drawing in your textbook shows four different situations in which a light ray is traveling from one medium into another.
00:07
In some of the cases, the reflection is not shown correctly.
00:11
For cases a, b, and c, the angle of incidence is 55 degrees.
00:16
For case d, the angle of incidence is 0 degrees.
00:22
Okay, so we know that the index of refraction is equal to c over n.
00:29
We also have snell's law.
00:33
N1, sine of theta 1 is equal to n2, sine of theta 2, which makes n1 over n2 sine of theta 2 over sine of theta 1.
00:50
So we can find the reflection, sorry, refraction.
00:57
Smell's law is with refraction.
01:00
So theta 2 is equal to the inverse sign of n1.
01:10
Sine of theta 1 over n2 we're going to use this so if it has an index of 1 .6 when it enters in a refractive index of 1 .4 based on the figure you have theta 2 as 46 degrees so this is when n1 is equal to 1 .4 n2 is equal 1 .6 theta 1 1 is 55 degrees.
01:47
You get theta 2 is 43 degrees.
01:52
Doing this same thing...