00:01
Hi everyone, this is the problem based on the concept of the force between two point charges is given by culemselm f is cut to k, q1, q22 by r squared.
00:44
Force on q1 due to q3 f31, k, q1, q1 3 upon r13 squared, substitute the value k.
01:11
9 into 10 to the power 9, q1, 8 into 10 to the power minus 6, 5 into 10 to the power minus 6 upon r13 is given 1 .3 in the problem.
01:31
So it is to be equal to 0 .213 newton.
01:39
And the direction of force you can find this is attractive force, sorry, repulsive, so it will be in this direction.
01:53
And force on q1 due to q2 will be attractive that will be in this direction.
02:04
Force on force on q1 due to q2...