00:01
Okay, to get this question started, we're going to use snells law.
00:04
So for the first part, we need to solve for the index of refraction for red light.
00:13
So we'll set this up.
00:15
This is for the red light.
00:18
We'll set this up index of refraction for the air, sign theta.
00:25
This is the angle of incidence.
00:28
And then index of refraction for red light, sign.
00:34
Theta red.
00:37
And we rearrange this to solve for the index of refraction.
00:44
So we can set it equal to this rearrangement here, all divided by sine theta red.
00:56
Plug in the values that are given to us, sine 26 divided by sine 10 .48.
01:11
And when we calculate this, we get an end.
01:14
Index of refraction of 2 .410, and that is for red.
01:20
We can even underline that in red.
01:23
And then next we'll do the same thing for blue.
01:29
So same setup using snell's law, index of angle of incidents there, index of reflection for blue, sign theta blue...