Question
The eccentricity and the coordinates of a focus of the conic $(5 x-10)^{2}+(5 y+15)^{2}=(x-2 y+7)^{2}$ are given by(a) $\sqrt{5},(2,-3)$(b) $\frac{1}{\sqrt{5}},(2,-3)$(c) $\frac{1}{\sqrt{5}},(3,-2)$(d) $\frac{1}{\sqrt{5}},(3,2)$
Step 1
Step 1: Start with the given equation of the conic, which is \((5x - 10)^2 + (5y + 15)^2 = (x - 2y + 7)^2\). Show more…
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