Question
The efficiency of Carnot's engine operating between reservoirs, maintained at temperature $27^{\circ} \mathrm{C}$ and $-123^{\circ} \mathrm{C}$ is(A) $0.5$(B) $0.4$(C) $0.6$(D) $0.25$
Step 1
The formula to convert Celsius to Kelvin is K = C + 273.15. Therefore, $27^{\circ} \mathrm{C}$ is equal to $27 + 273.15 = 300.15$ K and $-123^{\circ} \mathrm{C}$ is equal to $-123 + 273.15 = 150.15$ K. Show more…
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A Carnot's engine works between a source at a temperature of $27^{\circ} \mathrm{C}$ and a sink at $-123^{\circ} \mathrm{C}$. Its efficiency is (a) $0.5$ (b) $0.25$ (c) $0.75$ (d) $0.4$
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