Question

The electric field intensity between two large, charged, parallel metal plates is $6000 \mathrm{N} / \mathrm{C}$ The plates are $0.05 \mathrm{m}$ apart. What is the electric potential difference between them?

   The electric field intensity between two large, charged, parallel metal plates is $6000 \mathrm{N} / \mathrm{C}$ The plates are $0.05 \mathrm{m}$ apart. What is the electric potential difference between them?

Physics Principle and Problems

Physics Principle and Problems

Paul W. Zitzewitz,… 1st Edition

Chapter 21, Problem 16

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Solved by Expert Dading Chen

05/27/2020

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The electric field intensity between two large, charged, parallel metal plates is $6000 \mathrm{N} / \mathrm{C}$ The plates are $0.05 \mathrm{m}$ apart. What is the electric potential difference between them?

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Key Concepts

Uniform Electric Field Concept

In a uniform electric field, the electric field intensity is constant in both magnitude and direction. This simplifies the relationship between electric field intensity and electric potential difference, as the potential difference can be easily calculated using a linear relationship where V = E * d, making it an important concept in solving problems involving parallel plate configurations.

Electric Field Intensity

Electric field intensity describes the force per unit charge experienced by a charged particle placed within the field. It is a vector quantity and indicates both the magnitude and direction of the force that would act on a positive test charge. In a uniform electric field, the field intensity remains constant throughout the region between the charges.

Electric Potential Difference

The electric potential difference represents the work done per unit charge in moving a charge between two points within an electric field. It is a scalar quantity and is directly related to the energy change a charge experiences during its movement across the field. The potential difference is crucial for understanding how energy is transferred within an electric field.

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