Question
The electric flux is $\left(4.0 \mathrm{~V} \cdot \mathrm{m} / \mathrm{s}^{5}\right) t^{5}$ through a certain area of a dielectric that has dielectric constant $2.5 .$ (a) Find the displacement current through that area at $t=1.5 \mathrm{~s}$. (b) At what time was the displacement current $\frac{1}{6}$ as much? (b) $\overrightarrow{\boldsymbol{B}}_{0}=(0.260 \mathrm{~T}) \hat{\boldsymbol{\imath}} ?$
Step 1
Step 1: The displacement current $I_d$ is given by the equation $I_d = \epsilon_0 \frac{d\Phi_E}{dt}$, where $\Phi_E$ is the electric flux and $\epsilon_0$ is the permittivity of free space. Show more…
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