Question
The electric potential energy stored in the capacitor of a defibrillator is $73 \mathrm{~J}$, and the capacitance is $120 \mu \mathrm{F}$. What is the potential difference that exists across the capacitor plates?
Step 1
We are given U = 73 J and C = 120 μF. We need to find V. Rearranging the formula for V, we get: V^2 = (2 * U) / C Now, we can plug in the given values: Show more…
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