The electric potential of some configuration is given by the expression
$$
V(\mathbf{r})=A \frac{e^{-\lambda r}}{r}
$$
where $A$ and $\lambda$ are constants. Find the electric field $\mathbf{E}(\mathbf{r})$, the charge density $\rho(r)$, and the total charge Q. [Answer; $\left.\rho=\epsilon_{0} A\left(4 \pi \delta^{3}(\mathbf{r})-\lambda^{2} e^{-\lambda r} / r\right)\right]$