00:01
All right, guys, we're doing problem 100 of chapter 3 in chemistry, central science.
00:05
So we're giving the electron affinity of oxygen and the last energy of k2o.
00:09
They wanted to use the data to catch the second electron affinity of oxygen.
00:16
So the way that we have this reaction is 2k plus oxygen yields k2o.
00:23
So we're going to have our lattice energy, which is going to be 286.
00:37
That's 2 ,238, and that's going to be minus products.
00:49
It's going to be delta, remember, delta h reactions equal delta h products minus delta h reactants.
00:54
So we're going to have minus, where's our delta h of k2o, so minus 363 .2, minus our reactants.
01:10
So we have the delta h of formation of oxygen, so 2.
01:14
37 .5, then the first electron affinity, and then the second electron affinity.
01:24
So that's going to be ea2, then the delta h of formation for potassium, delta h of formation.
01:41
Then you got the ionization energy of potassium...