Question
The electronic configuration of an element $A$ is $1 s^{2}, 2 s^{2} 2 p^{5}$. The formula of substance containing only $A$ will be:(a) $A$$\square$ (b) $A_{2}$ [(c) $A_{5}$$\square$ (d) $A_{7}$ $-$
Step 1
This means that the element $A$ has 7 electrons in its outermost shell (2 from the $2s$ orbital and 5 from the $2p$ orbital). Show more…
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The electronic configuration of element $A$ is $1 s^{2}, 2 s^{2} 2 p^{6}$, $3 s^{2}$ while of the element $B$ is $1 s^{2}, 2 s^{2} 2 p^{5}$. The formula of the compound containing $A$ and $B$ will be: (a) $A B$ $\square$ (b) $A_{2} B$ (c) $A B_{2}$ $\square$ (d) $A_{2} B_{6}$
Electronic configuration of an element is $1 \mathrm{~s}^{2}, 2 \mathrm{~s}^{1}, 2 \mathrm{p}^{2} . \underline{\mathrm{It}}$ is (a) ground state configuration of $\mathrm{B}(Z=5)$ (b) excited state configuration of $\mathrm{B}$ (c) ground state configuration of $\mathrm{C}^{+}$ ion $(Z=6)$ (d) impossible configuration
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Exercises II
An atom $A$ has the electronic configuration of $1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2}$ $2 \mathrm{p}^{1}$. Atom $\mathrm{B}$ has the electronic configuration of $1 \mathrm{~s}^{2}$ $2 \mathrm{~s}^{2} 2 \mathrm{p}^{1}$. The empirical formula of the compound obtained from the reaction of $\mathrm{A}$ and $\mathrm{B}$ is: (a) $\mathrm{AB}$ (b) $\mathrm{AB}_{3}$ (c) $\mathrm{A}_{3} \mathrm{~B}_{3}$ (d) $\mathrm{A}_{2} \overrightarrow{\mathrm{B}}_{6}$
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