The energy of adsorption, $E_{\text {ads }}$, can be measured by the technique of temperature programmed desorption (TPD). In a TPD experiment, the temperature of a surface with bound adsorbate is changed according to the equation
$$
T=T_{0}+\alpha t
$$
where $T_{0}$ is the initial temperature, $\alpha$ is a constant that determines the rate at which the temperature is changed, and $t$ is the time. A mass spectrometer is used to measure the concentration of molecules that desorb from the surface. The analysis of TPD data depends on the kinetic model for desorption. Consider a first-order desorption process
$$
\mathrm{M}-\mathrm{S}(\mathrm{s}) \stackrel{k_{\mathrm{d}}}{\Longrightarrow} \mathrm{M}(\mathrm{g})+\mathrm{S}(\mathrm{s})
$$
Write an expression for the rate law for desorption. Use Equation 1 , Equation $29.37$, and your rate law to show that your rate law can be written as
$$
\frac{d[\mathrm{M}-\mathrm{S}]}{d T}=-\frac{[\mathrm{M}-\mathrm{S}]}{\alpha}\left(\tau_{0}^{-1} e^{-E_{\mathrm{at}} / R T}\right)
$$
With increasing temperature, $d[\mathrm{M}-\mathrm{S}] / d t$ initially increases, then reaches a maximum, after which it decreases. Let $T=T_{\max }$ be the temperature corresponding to the maximum rate of desorption. Use Equation 2 to show that at $T_{\max }$
$$
\frac{E_{\text {ads }}}{R T_{\max }^{2}}=\frac{\tau_{0}^{-1}}{\alpha} e^{-E_{a b} / R T_{\max }}
$$