00:01
So this problem wants us to determine the increase in temperature of the water in 1r, given that all of the energy released by alpha decay goes into hitting the water, given that we have a plutonium sample.
00:23
So let's denote the changing temperature as delta t.
00:29
And if this is the sample, so we have 239, potonium 239, it goes in alpha decay, becomes uranium 235 and we have here the alpha particle which is same atomic mass in atomic number of helium atom so we can derive an expression for the changing temperature by the formula of heat which is q equals to product of the mass of the water the specific heat of the water and the changing temperature is the heat required to raise the temperature of the water and since you've stated that all of the energy release was converted to heat, then we can say that the net energy by the decay is equals to the...
01:22
And note that the total energy due to decay is the product of the total number of decays and the energy per one decay.
01:38
And the total number of decays is the difference of the initial number of nuclei and the remaining.
01:44
Nuclear after some time due to after some time as it decays.
01:51
And the energy per decay is the product of the change in mass from atom multiplied by the speed of light squared.
02:07
And the remaining nuclei is equals to this.
02:21
So we can further simplify our equation to this.
02:26
Note that lambda here is the decay constant of the plutonium in this example.
02:31
So we have ln of 2 over the half life.
02:35
And here is the elapsed time, which is also given.
02:47
And the change in mass of the atom here is this.
02:55
The sum of the mass of uranium atom and the helium atom minus the mass of the plutonium atom.
03:16
And the initial number of nuclei is the quotient of the given mass and the mass of the atom.
03:43
Now, let us solve this.
03:52
So the given mass of the plutonium, which is 50 grams.
03:55
So let's convert it to kilograms by this factor.
04:00
And the mass of protonium atom is 239 .052 -158u...