Question
The enthalpy change involved in the oxidation of glucose is $-2880 \mathrm{~kJ} / \mathrm{mol}$. Twenty five per cent of this energy is available for muscular work. If $100 \mathrm{~kJ}$ of muscular work is needed to walk $1 \mathrm{~km}$, what is the maximum distance that a person will be able to walk after eating $120 \mathrm{~g}$ of glucose?(a) $19.2 \mathrm{~km}$(b) $9.6 \mathrm{~km}$(c) $2.4 \mathrm{~km}$(d) $4.8 \mathrm{~km}$
Step 1
The formula for this is given mass divided by molar mass. The molar mass of glucose is 180 g/mol. So, the number of moles of glucose is $\frac{120 \, \text{g}}{180 \, \text{g/mol}} = 0.67 \, \text{moles}$. Show more…
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The enthalpy change involved in the oxidation of glucose is $-2880 \mathrm{~kJ} \mathrm{~mol}^{-1}$. Twenty five per cent of this energy is available for muscular work. If $100 \mathrm{~kJ}$ of muscular work is needed to walk one kilometre, what is the maximum distance that a person will be able to walk after consuming $120 \mathrm{~g}$ of glucose? (a) $7.9 \mathrm{~km}$ (b) $9.7 \mathrm{~km}$ (c) $4.8 \mathrm{~km}$ (d) $8.4 \mathrm{~km}$
The enthalpy change involved in the oxidation of glucose is $-2880 \mathrm{~kJ} \mathrm{~mol}^{-1}$. Twenty five percent of this energy is available for muscular work. If 100 $\mathrm{kJ}$ of muscular work is needed to walk one kilometer, what is the maximum distance that a person will be able to walk eating $120 \mathrm{~g}$ of glucose? a. $7.9 \mathrm{~km}$ b. $9.7 \mathrm{~km}$ c. $4.8 \mathrm{~km}$ d. $8.4 \mathrm{~km}$ [IIT 1997]
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