The enthalpy of combustion of methane is -890 kJ. The volume of methane at 0 ^∘ C and 1 atm to

step 1 First of all, let's have a look what all is given in the problem. Given is enthalpy of combustio

The enthalpy of combustion of methane is -890 kJ. The...

The enthalpy of combustion of methane is $-890 \mathrm{~kJ}$. The volume of methane at $0{ }^{\circ} \mathrm{C}$ and 1 atm to be burnt to produce $2670 \mathrm{~kJ}$ heat is
(a) $33.61$
(b) $67.21$
(c) $7.471$
(d) $11.21$

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Ideal Gas Law and Standard Temperature and Pressure (STP)

The ideal gas law relates the pressure, volume, temperature, and number of moles of a gas, providing a framework to convert between these quantities. Under conditions defined as STP (0°C and 1 atm), the molar volume of an ideal gas is approximately constant, which aids in relating the number of moles to the volume of gas.

Enthalpy of Combustion

Enthalpy of combustion is the heat released when one mole of a substance burns completely in oxygen. This thermodynamic property is used to determine the energy content of fuels and is essential in calculating how much fuel is required to release a given amount of energy.

Stoichiometry and Energy Relationships

Stoichiometry involves the quantitative relationship between reactants and products in a chemical reaction. When combined with energy data like the enthalpy of combustion, stoichiometry helps in computing the number of moles of a fuel needed to yield a specific amount of energy.

Transcript

Please give Ace some feedback