00:01
So this particular question gives us two amounts of enthalpy of combustion per mole of reactant.
00:09
So for the first reaction, the enthalpy of combustion is this negative 393 .7.
00:14
But because in the second reaction, we need to balance by putting in twos, that would mean that our negative 283 .3.
00:26
3 would now become negative 56 .6 .6 .6 per mole reaction now that we've changed the coefficient.
00:37
And this particular question asks us to find the delta h for 2c plus o2 yields 2co.
00:47
And so what we're going to need to do is reverse and keep.
00:54
Okay? so when we reverse and keep, but we double this one, what that means is we will wind up, and i'm just going to give you this one is going to be boxed in there.
01:07
If i double the top one, it's 2c plus 202 yields 2c02, and that would be 2 times negative 393 .7, because when you double the coefficients, you double the heat.
01:34
And if we reverse, the second one, that becomes 2 co2 yields 2c plus o2, and now one of my o2s cancels and my co2s cancel.
01:51
And i wound up with 2c plus o2 yields 2co, which is the overall reaction...