00:01
And this problem, we have magnesium oxide, or we have magnesium that's combusting with oxygen to make magnesium oxide.
00:09
So it's a solid fuel.
00:12
So we're told that the enthalpyal formation of magnesium oxide, which is a solid also, is minus 602 megajoules per kilamol at 25c.
00:28
And we know that the melting point of magnesium oxide is approximately, 3 ,000 kelvin.
00:37
So we are not sure exactly when we react this, whether this is a solid or a liquid.
00:45
And let's see here.
00:46
There increased an entropy between room temperature and 3 ,000 kelvin, where it melts, is about 120, 128 megajoules per kilmole.
01:00
And then we have the entropy of sublimation.
01:02
I guess this never goes through a liquid phase, so it just sublimates to a gas.
01:06
The entropy of sublimation at 3 ,000 kelvin is estimated at 418 megajoules per kilomole.
01:15
And the specific heat of the magnesium oxide vapor above 3 ,000 kelvin is estimated to be 37 .24 kilojoules per kilomore calvin.
01:28
Okay, so we got a lot of information here about magnesium or magnesium oxide anyway.
01:33
So we are asked to determine the entropy of combustion for a kilogram of this stuff, or per kilogram.
01:47
So the entropy of combustion is just going to be the entropy of the reactants, or the products minus that of the reactants.
01:58
Well, there's no entropy of formation of these reactants.
02:02
This is base.
02:03
These are base molecules or base atom.
02:08
And so that means that the entropy of combustion per kilomole is just the entropy of formation of the magnesium oxide, which is 602 megajoules per kilomole or minus that.
02:21
But we were asked for it in kilograms, so we need to divide by the molecular mass of magnesium, which we can look up.
02:28
And so we get minus 247, minus 24 ,000, minus 24 ,000, minus 24 ,000, minus 24 ,000, minus 24, 7.
02:38
100 kilojoules per kilogram...