Question
The equation for the rate constant is $k=\mathrm{Ae}^{-\mathrm{E}_{2} / \mathrm{RT}} . \mathrm{A}$ chemical reaction will proceed more rapidly if there is a decrease in:(a) $k$(b) A(c) $\mathrm{E}$(d) $\mathrm{T}$
Step 1
Step 1: From k = A e^{-E/RT}, the reaction rate increases as the rate constant k increases (rate ā k). Show more…
Show all steps
Your feedback will help us improve your experience
Hunza Gilgit and 88 other Chemistry 102 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The equation for the rate constant is $k=\mathrm{Ae}^{\mathrm{EakT}}, \mathrm{A}$ chemical reaction will proceed more rapidly if there is a decrease in (a) $k$ (b) $\mathrm{A}$ (c) $\mathrm{E}$ (d) $\mathrm{T}$
The rate constant is given by the equation: $K=P \cdot A \cdot e^{-E_{a} / R T}$. Which factor should register a decrease for the reaction to proceed more rapidly? (a) $T$ (b) $A$ (c) $E_{\text {a }}$ (d) $P$
Chemical Kinetics
Exercises I
The rate constant is given by the equation $\mathrm{K}=\mathrm{P} . \mathrm{Ze}^{-\mathrm{EKT}}$. Which factor should register a decrease for the reaction to proceed more rapidly (a) $\mathrm{T}$ (b) $\mathrm{Z}$ (c) $\underline{\mathrm{E}}$ (d) $\mathrm{P}$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD