Question
The equation of a circle which passes through the origin and cuts off intercepts 'a' and 'b' on the axes is(a) $x^{2}+y^{2}=a b$(b) $x^{2}+y^{2}-a x-b y=0$(c) $x^{2}+y^{2}=a+b$(d) $x^{2}+y^{2}-2 a x-2 b y=0$
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This means that the circle passes through the points (a,0) and (0,b). Show more…
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