Question
The equation of a wave travelling on a stretched string is:$$y=4 \sin 2 \pi\left(\frac{t}{0.02}-\frac{x}{100}\right)$$Here $x$ and $y$ are in $\mathrm{cm}$ and $t$ is in second. The speed of wave is:(a) $50 \mathrm{~m} / \mathrm{s}$(b) $40 \mathrm{~m} / \mathrm{s}$(c) $50 \mathrm{~cm} / \mathrm{s}$(d) $40 \mathrm{~cm} / \mathrm{s}$
Step 1
02}-\frac{x}{100}\right) $$ From this equation, we can identify the angular frequency $\omega$ and the wave number $k$ as follows: $$ \omega = 2\pi \times \frac{1}{0.02} \quad \text{and} \quad k = 2\pi \times \frac{1}{100} $$ Show more…
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