Question
The equation of an ellipse with its center at the origin can be written as$\frac{x^{2}}{a^{2}}+\frac{y^{2}}{a^{2}\left(1-e^{2}\right)}=1$Show that as $e \rightarrow 0$, with $a$ remaining fixed, the ellipse approaches a circle.
Step 1
Step 1: The given equation of the ellipse is $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{a^{2}\left(1-e^{2}\right)}=1$. Show more…
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