Question
The equation of the circle touching the lines given by $|x-2|+|y-3|=4$ is(a) $x^{2}+y^{2}+4 x+6 y-5=0$(b) $x^{2}+y^{2}-4 x-6 y+5=0$(c) $x^{2}+y^{2}-4 x+6 y-5=0$(d) $x^{2}+y^{2}-4 x-6 y-5=0$
Step 1
This equation can be transformed into $|X|+|Y|=4$ when the origin is shifted to the point (2,3) without changing the direction of the axes. Here, $X=x-2$ and $Y=y-3$. Show more…
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