Question
The equation of the circle with latus rectum of $y^{2}+4 y+4 x+2=0$ as a diameter is(a) $4\left(x^{2}+y^{2}+x+4 y\right)+1=0$(b) $4\left(x^{2}+y^{2}+4 y\right)+1=0$(c) $x^{2}+y^{2}+x+4 y+1=0$(d) $x^{2}+y^{2}+3 x+4 y+1=0$
Step 1
This is the equation of a parabola. We can rewrite this equation in the standard form of a parabola by completing the square. Show more…
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