Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

The equilibrium constant for the reaction $\mathrm{A}+2 \mathrm{B} \rightleftharpoons 3 \mathrm{C}$ is 0.25 at a certain temperature. Which diagram shown here corresponds to the system at equilibrium? If the system is not at equilibrium, predict the direction of the net reaction to reach equilibrium. Each molecule represents 0.40 mole and the volume of the container is $2.0 \mathrm{L}$. The color codes are $\mathrm{A}=$ green, $\mathrm{B}=\mathrm{red}$ $\mathrm{C}=$ blue.

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

None corresponds to equilibrium.(a) $Q=1.5 ;$ to the left(b) $Q=0.44 ;$ to the left(c) $Q=0.28 ;$ to the left

Chemistry 102

Chapter 14

Chemical Equilibrium

Carleton College

University of Central Florida

University of Maryland - University College

Brown University

Lectures

10:03

In thermodynamics, a state of thermodynamic equilibrium is a state in which a system is in thermal equilibrium with its surroundings. A system in thermodynamic equilibrium is in thermal equilibrium, mechanical equilibrium, electrical equilibrium, and chemical equilibrium. A system is in equilibrium when it is in thermal equilibrium with its surroundings.

00:54

In chemistry, chemical equilibrium (also known as dynamic equilibrium) is a state of chemical stability in which the concentrations of the chemical substances do not change in the course of time due to their reaction with each other in a closed system. Chemical equilibrium is an example of dynamic equilibrium, a thermodynamic concept.

05:17

The equilibrium constant f…

07:03

The reaction $\mathrm{A}_{…

07:35

02:06

00:53

05:13

stance of this question was simply to solve for Q and then determine whether or not Q is greater than less than or equal to K. Here's our chemical reaction. Here's our K expression, and it should equal 2.4 point 25 As the problem describes. So for Q. We need to take the concentration of C and Cubit. See is blue. There are three blue circles. Each blue circle corresponds to 30.4 moles, and then, to get our concentration, we need to divide by the two leaders. So we've got our three multiplied by 30.4, divided by our two leaders, and we're going to cube that whole thing. Then we will divide by concentration of a A is green. There are two A molecules each corresponds to 0.4. Moles were then divide that by the two leaders. Then, for the B concentration. B is red. There are three red spheres. Each sphere corresponds to 30.4 moles, but then divide that by two leaders and square it because of the squared value up here. And we get a cue value of 1.5. And if you remember from ah, chemical equilibrium salving for que. When Q is greater than K, we have too much product, not enough reactant. So the equilibrium shifts to the left for the next one. We have two blue spheres. Each correspond 2.4 moles. Divide by the two leaders and then cubit because this is now our new C concentration. Lose something similar with the with a A is green green is two spheres, so two times 20.4 divided by our two leaders. We don't raise a to any power. And then for B b is red and there are four red spheres. So four times point for divided by the two leaders. And then we're going to square it and we get a K value of 0.25 So be appears to be at equilibrium because Q is equal to K. Then for the last one c, we have one, um, one sphere for ah, Compound C, and we'll take in that correspondence. 2.4 moles will then divide that by two to get our concentration of C and then cubit, and then we go to a athe green spheres. There are four of them, so before times 0.4 to get a concentration. We divide the moles by the volume two leaders and then for B B is red. There are three red spheres, three times 30.4 divided by the two leaders, and then we square it. When we carry out this calculation, we get Q is equal 2.28 and just the opposite from appear. When Q is less than K, we don't have enough product. So in order to make more product, this equilibrium is going to shift to the right.

View More Answers From This Book

Find Another Textbook