The equilibrium constant for the reaction
$\mathrm{H}_3 \mathrm{PO}_4 \rightleftharpoons \mathrm{H}^{+}+\mathrm{H}_2 \mathrm{PO}_4^{-}$is $\mathrm{K}_1$,
for reaction $\mathrm{H}_2 \mathrm{PO}_4 \rightleftarrows \mathrm{H}^{+}+\mathrm{HPO}_4{ }^{2-}$ is $\mathrm{K}_2$ and
for reaction $\mathrm{HPO}_4{ }^{2-} \rightleftharpoons \mathrm{H}^{+}+\mathrm{PO}_4{ }^{3-}$ is $\mathrm{K}_3$.
The equilibrium constant ( K ) for
$\mathrm{H}_3 \mathrm{PO}_4 \rightleftarrows 3 \mathrm{H}^{+}+\mathrm{PO}_4{ }^{3-}$ will be
(a) $\mathrm{K}_1, \times \mathrm{K}_2 \times \mathrm{K}_3$
(b) $\mathrm{K}_1 / \mathrm{K}_2 \mathrm{~K}_3$
(c) $\mathrm{K}_2 / \mathrm{K}_1 \mathrm{~K}_3$
(d) $\mathrm{K}_1,+\mathrm{K}_2+\mathrm{K}_3$