The equilibrium constant for the reaction: SO3( g) ⇌SO2( g)+(1)/(2) O2( g) is Kc=4.9 ×10^-2. the

Name: Problem 119, Chapter 7: Objective Chemistry for NEET
Uploaded: 2021-12-05T03:38:18-08:00
Duration: 2 min 48 s
Channel: Rajesh Singh
Description: The equilibrium constant for the reaction: SO3( g) ⇌SO2( g)+(1)/(2) O2( g) is Kc=4.9 ×10^-2. the value of K for the reaction 2 SO2( g)+O2( g) ⇌2 SO3( g) will be (a) 416 (b) 2.40 ×10^-3 (c) 9.8 ×10^-2 (d) 4.9 ×10^-2

step 1 Here in this question we are given with the equilibrium constant for the reaction which is SO3.

Question

The equilibrium constant for the reaction: $\mathrm{SO}_{3}(\mathrm{~g}) \rightleftharpoons \mathrm{SO}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g})$ is $K_{c}=4.9 \times 10^{-2}$. the value of $K$ for the reaction $2 \mathrm{SO}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{SO}_{3}(\mathrm{~g})$ will be (a) 416 (b) $2.40 \times 10^{-3}$ (c) $9.8 \times 10^{-2}$ (d) $4.9 \times 10^{-2}$

   The equilibrium constant for the reaction:
$\mathrm{SO}_{3}(\mathrm{~g}) \rightleftharpoons \mathrm{SO}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g})$
is $K_{c}=4.9 \times 10^{-2}$. the value of $K$ for the reaction $2 \mathrm{SO}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{SO}_{3}(\mathrm{~g})$ will be
(a) 416
(b) $2.40 \times 10^{-3}$
(c) $9.8 \times 10^{-2}$
(d) $4.9 \times 10^{-2}$

Objective Chemistry for NEET

A.K. Singhal, U. K.… 1st Edition

Chapter 7, Problem 119

Instant Answer

Solved by Expert Rajesh Singh

12/05/2021

Step 1

Step 1: The equilibrium constant for the given reaction is defined as: \[K_{c1} = \frac{[\mathrm{SO}_{2}][\mathrm{O}_{2}]^{1/2}}{[\mathrm{SO}_{3}]}\] Show more…

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The equilibrium constant for the reaction: $\mathrm{SO}_{3}(\mathrm{~g}) \rightleftharpoons \mathrm{SO}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g})$ is $K_{c}=4.9 \times 10^{-2}$. the value of $K$ for the reaction $2 \mathrm{SO}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{SO}_{3}(\mathrm{~g})$ will be (a) 416 (b) $2.40 \times 10^{-3}$ (c) $9.8 \times 10^{-2}$ (d) $4.9 \times 10^{-2}$

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Key Concepts

Reaction Stoichiometry and Its Effect on Kc

The equilibrium constant is dependent on the stoichiometry of the reaction. When the reaction is reversed, the equilibrium constant becomes the reciprocal of the original. Additionally, when the coefficients of a balanced equation are multiplied by a factor, the equilibrium constant is raised to that power, reflecting the change in the reaction's stoichiometry.

Equilibrium Constant (Kc)

The equilibrium constant expresses the ratio of the concentrations of products to reactants at equilibrium for a given chemical reaction. Its value is specific to the reaction at a given temperature and is used to predict the extent of the reaction under equilibrium conditions.

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