The equilibrium constant value for the reaction $\mathrm{N}_2(\mathrm{~g})+3 \mathrm{H}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_3(\mathrm{~g})$ is $1.48 \times 10^{-5}$, the value for the reaction $1 / 2 \mathrm{~N}_2(\mathrm{~g})+3 / 2 \mathrm{H}_2(\mathrm{~g}) \rightleftharpoons \mathrm{NH}_3(\mathrm{~g})$ is $\mathrm{n} \times 10^{-3}$ where n is
(a) 1.85
(b) 3.85
(c) 4.85
(d) 10