00:01
Hello everyone here it is given the essential structure of a certain type of aircraft turn indicator as shown in the figure having the spring ac and bd are initially stressed and exert equal vertical force at a and b when the airplane is traveling in a straight path each spring having the spring constant 600 newton per meter and a uniform disk having the mass 250 gram that is 0 .25 kg and spin at constant rate of 12 ,000 rpm it can be converted into radian and its value will be 1256 .6 radian per second and it will be along x -axis.
01:30
We have determined the angle through which the yop a b will rotate when the pilot execute so we have to calculate theta of a v when pilot execute when pilot execute horizontal turn of radius 800 meter to the right with 720 km per hour let us start solving we also indicate whether point a will move up or down let us start solving it.
02:58
We will draw the geometrical figure of the disk.
03:09
This is the centroid.
03:12
This is y -axis.
03:14
This is x -axis.
03:17
This is z -axis.
03:19
Here it is omega -x.
03:30
This is omega -y.
03:34
I -cap, j -cap.
03:37
Aircraft speed is given.
03:39
720 km per hour.
03:42
That is 200 meter per second.
03:45
And radius of the turn is given 800 meters.
03:51
So omega x already i have written 1256.
03:56
0 .6 radian per second.
03:58
Omega y will be minus b upon r that is 200 by 800.
04:07
It will be minus 0 .25 radian per second.
04:13
Omega z is zero.
04:15
Now angular momentum about g point, it will be ix, omega x, i cap, minus iy, omega -y -j -j -cap.
04:33
Angular velocity of reference frame, gx, y, z is called to omega -j -cap.
05:05
Rate of change of angular momentum, omega -cross.
05:32
This value is zero because it is moving with constant angular velocity...