Question
The expression for centripetal force depends upon mass of body, speed of the body and the radius of circular path. Find the expression for centripetal force:(a) $F-\frac{m v^{2}}{2 r^{3}}$(b) $F=\frac{m v^{2}}{r}$(c) $F=\frac{m v^{2}}{2}$(d) $F \cdot=\frac{m^{2} v^{2}}{2 r}$
Step 1
We can represent these dependencies as $F = m^a v^b r^c$, where a, b, and c are the powers we need to determine. Show more…
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The expression for centripetal force $(F)$ depends upon mass of body $(m)$, speed $(v)$ of the body and the radius ( $r$ ) of circular path will be expression for centripetal force (a) $F=\frac{m v^{2}}{2 r^{3}}$ (b) $F=\frac{m v^{2}}{r}$ (c) $F=\frac{m v^{2}}{r^{2}}$ (d) $F=\frac{m^{2} v^{2}}{2 r}$
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the expression for centripetal force depend on mass of body speed of a body and the radius of a circular path find the expression of centripetal
Centripetal Force An object of mass $m$ moves at a constant speed $v$ in a circular path of radius $r .$ The force required to produce the centripetal component of acceleration is called the centripetal force and is given by $F=m v^{2} / r .$ Newton's Law of Universal Gravitation is given by $F=G M m / d^{2}$, where $d$ is the distance between the centers of the two bodies of masses $M$ and $m$, and $G$ is a gravitational constant. Use this law to show that the speed required for circular motion is $v=\sqrt{G M / r}$
Vector-Valued Functions
Tangent Vectors and Normal Vectors
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