00:03
In this problem, we have a microscope, and we have the information for the focal length of the objective and the ips, these are the values.
00:17
And also, we got the value of the length of the tube that is this one.
00:24
In the first part of the problem, we want to compute the value of that total angular magnification.
00:31
So we must remember that for a microscope, that is formed by.
00:37
Two lenses, this total angular modification is just the product of the magnification produced by each lens.
00:46
For the first lens, for the objective, this is just minus l over the focal length of this lens.
00:56
And for the second length, this is n over the focal length of this second lens.
01:08
So we only need to replace the values here.
01:13
For l, this is 0 .18.
01:18
For f0, this is just 0 .144...