00:01
So we have some information, and we're going to let d stand for the difference between after minus before, and they're looking at the crime after they've implemented some programs.
00:13
And when i took the difference this way, the values that i had were, and let me quick just give you those, and you can double check me.
00:22
I have negative 12, 0, negative 1, 1, negative 9, 1, negative 5.
00:30
Let me arrow down, negative 4, and that's it.
00:35
So we have a sample size of 8 differences.
00:40
And we want to find, we'll be assuming that the mean difference is equal to 0, and alternately that the mean difference is actually negative, meaning that this number after is smaller than before so that we think that it's decreased.
00:59
And we have our data.
01:01
We know we have eight values.
01:04
And let me quick put in my, give you my mean and my standard deviation for those distributions, or for that distribution of eight numbers.
01:14
So we have that the x bar for those values is negative 3 .625.
01:22
Our standard deviation for those eight values is 4 .8385.
01:29
And we want to find our test statistic.
01:32
And before we do that, we're also using a 1 % significance level.
01:36
So let's find that critical t value right now.
01:39
And so that critical t value, we want to put all of that 0 .01 down in this tail, since we're doing a one -tail test, and this is where we would be rejecting our null and saying that we have evidence that it's actually smaller, that it has decreased the number of crimes with that federal program.
01:57
And let's find what that t value is.
01:59
That t value that will have seven degrees of freedom and it will have 1 % in the lower tail is going to be negative.
02:06
And let me get that lined up, seven degrees of freedom.
02:10
And 1%, we have 2 .998.
02:13
So this will be negative 2 .998...