The figure shows a circuit containing an electromotive force, a capacitor with a capacitance of $C$ farads $(\mathrm{F}),$ and a resistor with a resistance of $R$ ohms $(\Omega) .$ The voltage drop across the capacitor is $Q / C,$ where $Q$ is the charge (in coulombs), so in this case Kirchhoff's Law gives
$$R I+\frac{Q}{C}=E(t)$$
But $I=d Q / d t($ see Example 3 in Section 3.7$),$ so we have
$$R \frac{d Q}{d t}+\frac{1}{C} Q=E(t)$$
Suppose the resistance is $5 \Omega,$ the capacitance is 0.05 $\mathrm{F}$ , a battery gives a constant voltage of $60 \mathrm{V},$ and the initial charge is $Q(0)=0 \mathrm{C} .$ Find the charge and the current at time $t$.