Question
The figure shows two metal plates $\mathrm{A}$ and $\mathrm{B}$ which are square in shape and have same thickness $t$. The side of $B$ is twice that of A. Current flows through them in the direction as shown by the arrow marks. The ratio of resistance of $\mathrm{A}$ to that of $B$ is.(A) $1: 2$(B) $2: 1$(C) $1: 1$(D) $1: 4$
Step 1
The area of block A, $A_1$, is equal to the length times the thickness, so $A_1 = lt$. The area of block B, $A_2$, is equal to twice the length times the thickness, so $A_2 = 2lt$. Show more…
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