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All right, guys.
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Problem number 28 of chapter 9 in chemistry, central science.
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So the figure that you see here contains bolns shows three possible shapes of an af4 molecule.
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For each shape, give the electron domain geometry on which the molecule, on which the molecular geometry is based.
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So let me try to separate these.
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So this is a square planar structure.
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Oh, sure? so that's evident that it has four bonds and two long pairs.
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So its electron domain geometry would be octahedral.
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All right, for this one, this is a tetrahedral molecular geometry, and tetragil is also the electron domain geometry.
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And for the third one, that is a seesaw structured, and that's a trigonal bipyramid electron domain geometry.
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So part b, for each shape, how many non -bonding electron domains are there on atom a? so this is octahedral.
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So there are, then we have four bonds.
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That means we have two non -bonding domains.
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Here we have zero because it's tetrahedral, both molecular and electron domain geometry.
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And since this is trigonal biphem electron domain geometry, we have one.
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Non -bonded pair, one loan pair.
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So for part c, they want to know which of the following elements will lead to an a4 molecule in shape 3.
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So i'm going to move, going to get rid of this.
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So in fact, let me draw this.
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Just this loan pair should be there.
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So let's see.
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Let's draw our domain structure.
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Two, three.
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So we have to take.
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Count how many electrons we have...