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The first line of the Balmer series occurs at a wavelength of $656.3 \mathrm{nm} .$ What is the energy difference between the two energy levels involved in the emission that results in this spectral line?

$E=6.63 \cdot 10^{-34} \cdot \frac{m^{2} \cdot k g}{s} \cdot \frac{3 \cdot 10^{8} \frac{m}{s}}{656.3 n m \cdot \frac{m}{10^{9} n m}} \approx 3.03 \cdot 10^{-19} J$

Chemistry 101

Chapter 7

Quantum Theory and the Electronic Structure of Atoms

Electronic Structure

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Lectures

04:49

In chemistry and physics, electronic structure is the way the electrons of an atom are arranged in relationship to the nucleus. It is determined by the subshells the electrons are bound to, which are in turn determined by the principal quantum number ("n") and azimuthal quantum number ("l"). The electrons within an atom are attracted to the protons in the nucleus of that atom. The number of electrons bound to the nucleus is equal to the number of protons in the nucleus, which is called the atomic number ("Z"). The electrons are attracted to the nucleus by this mutual attraction and are bound to the nucleus. The electrons within an atom are attracted to each other and this attraction determines the electron configuration. The electron configuration is described by the term symbol, which is the letter used to identify each subshell.

16:45

In physics, the wave–particle duality is the concept that every object or process, no matter how large or how small, behaves as both a wave and a particle. The wave–particle duality is one of the central concepts in quantum mechanics.

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The first line of the Balm…

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6.29 The first line of the…

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What is the difference in …

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One spectral line in the h…

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Find the wavelength of the…

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Determine the wavelength, …

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Determine the wavelengths,…

04:44

I guess this question is related to a bomber. Siri's So Bomber. Siri's show, the first time of all mysteries shows as the electron falls from the third Quanta and Equal Street to the second quarter and equals two. All right, and this question asked, What is the energy change associate ID when that happens? So we know that the change in energy is equal to Plank's constant. Where is constant times, frequency of the frequency? So we can also say that it's able to place constant times, speed of light, divided by the wavelength. This is used. This is equal to the frequency. So when we put this in, we say that we cause me because we know that the first line shows at 600 and 56.3 nana meters. We know we can find the frequency associated with that. We know the place. Constant 6.63 times, 10 to the native, 34th jewels per second. We know that the speed of light is three times 10 three times 10 to the eighth meters per second, and we know there's a wavelength is 656 0.3 times 10 to the negative night meters. We know that because it gave us a nana meters know that anything in nano meters is times 10 to the negative night. And we need to have us in meters because as you can see, speed of light is in meters per second. So we need those to cancel out. So they meters, these you're gonna cancel out in these seconds, these two are gonna cancel out. So we're gonna leave us with jewels, which is the correct unit, because we're looking for the change in energy. Okay, so we played this end of the equation will be put this into the calculator, change in energy. It's going to be 3.3 times 10 to the negative 19th jewels. That is how much energy is emitted as electromagnetic radiation as the electron falls from the third quant ized state to the second quantum state of a hydrogen atom. Thank you very much.

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