00:02
All you everyone here it is given in a co -generating steam power plant.
00:11
The turbine received steam from a high pressure stream drop and low pressure speed drop as through the figure.
00:19
1 and 2.
00:22
The condenser is made as to close its exchanger used to heat water running at a separate loop.
00:32
For the sprint heating, the high temperature, heat heat at 30 megawatts and low temperature heater add 31 megawatts to the district heating water flow find the power co -generated we have to calculate power co -generated that we have to calculate and temperature of excess we have to find let it start solving it in next state from table we are writing in left state using david b .b .b .b .1 is 3 ,445 .9 kilojoules per k.
01:56
An entropy of first inlet is 6 .9108 kilojoules per kg per second, 2858 5 .5 .4, below jules per k .g.
02:26
And entropy is 7 .05 92 kilojoules per k.
02:37
So, total flow rate of the flip 27 kg per second.
03:03
Assume a reversible turbine and the two flow can mix without entropy generation.
03:10
Assuming, assume a reversible process.
03:25
And two in legs and two flows mixed without entropy generation so by energy equation we can write and by entropy equation so from here entropy of mixture we will get 6 .93 .83 0 jr per kg per gallon in is state 3 and trophy is called to entropy of mixture so as 3 is 2 6 3 2 .4 0 2 o 2 kg and quantity of fluid is 0 966 and state 4 as 4 is equal to as mixed and thermal capacity of the fluid is or beach up you have to collect from the habit.
07:17
So we've done.
07:24
Total from equation 1.
07:32
M1, rate of flow of first period is 22 kg per second...