00:01
Okay, so we're starting with this pretty large molecule.
00:05
And one of the first things to notice is this is going to form a five -numbered ring with two nitrogen's, one carbon away from each other.
00:13
So the easiest way we can do that is having this already nucleophilic nitrogen attack this electrophilic center at the carbonyl.
00:23
All right, so that is going to give us the following product, where we're going to have n forming that ring structure.
00:31
All right.
00:45
So now this ring structure gets pretty interesting, right? because i've got this oh right here, but i also have the rest of the ring.
00:54
So let's just draw that right quick.
01:14
So nothing to note is that this now has a very positive charge on that nitrogen, which is probably not going to be very favorable.
01:22
And i also neglected to draw.
01:25
There was also a hydrogen right there, which is why this nitrogen has a positive charge.
01:29
A small potential next step for this reaction is for this oxygen just to pick up this hydrogen right here.
01:39
So what that's going to do, and i'm just going to erase this, is that's, for one, going to get rid of the hydrogen and thus the positive charge, but it's also going to make this have a positive charge right there.
01:53
So what that means is that now becomes a very good leaving group.
02:01
So what we're going to have happened, excuse me, is this bond.
02:05
I'm just kind of, let me do this in red, kind of jumping, right? so that will yield something that looks a little more like what our final product is going to look like.
02:20
All right, and i'm going to, instead of drawing that whole thing, kind of just draw this squiggly line.
02:39
I'm going to use that to kind of indicate that nothing else has really changed in this reaction, or on the chains, rather...