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Problem 10 Easy Difficulty

The flexible loop in Figure P20.10 has a radius of 12 cm and is in a magnetic field of strength 0.15 T. The loop is grasped at points A and B and stretched until its area is nearly zero. If it takes 0.20 s to close the loop, what is the magnitude of the average induced emf in it during this time?

Answer

0.0339 \text { Vclock wise }

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Video Transcript

the average induced M F per unit Time here is absolutely equal to minus the number of turns times the change and magnetic flux. Delta Phi divided by the change in time delta T So this is equal to minus the number of turns. Delta Phi is equal to the initial magnetic field, which is zero minus are the initial flux, which is zero minus the final flux, which is be a co sign of data divided by again delta T. So this is equal to minus the number of turns multiplied by negative magnetic field times. The area which is pi r squared, divided by Delta t. So the negative signs are gonna cancel and then plugging all those values that we know into this expression, we find that the, uh, induce cmf here zero point zero 34 in the units Here are volts, so we can go ahead and box set in is our solution to the question

University of Kansas
Top Physics 102 Electricity and Magnetism Educators
Elyse G.

Cornell University

Marshall S.

University of Washington

Farnaz M.

Other Schools

Aspen F.

University of Sheffield

Physics 102 Electricity and Magnetism Bootcamp

Lectures

Join Bootcamp