Question
The flexible loop in Figure P20.10 has a radius of 12 cm and is in a magnetic field of strength 0.15 T. The loop is grasped at points A and B and stretched until its area is nearly zero. If it takes 0.20 s to close the loop, what is the magnitude of the average induced emf in it during this time?
Step 1
Step 1: The average induced emf per unit time is given by the formula: \[ \frac{-N \Delta \Phi}{\Delta t} \] where \(N\) is the number of turns, \(\Delta \Phi\) is the change in magnetic flux, and \(\Delta t\) is the change in time. Show more…
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The flexible loop in the figure below has a radius of 13 cm and is in a magnetic field of strength 0.12 T. The loop is grasped at points A and B and stretched until its area is nearly zero. If it takes 0.25 s to close the loop, what is the magnitude of the average induced emf (in mV) in it during this time?
The flexible loop in Figure $\mathrm{P} 31.3$ has a radius of 12.0 $\mathrm{cm}$ and is in a magnetic field of magnitude 0.150 $\mathrm{T}$ . The loop is grasped at points $A$ and $B$ and stretched until its area is nearly zero. If it takes 0.200 $\mathrm{s}$ to close the loop, what is the magnitude of the average induced emf in it during this time interval?
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