00:01
Okay, so this molecule here is two bromopentane.
00:05
And so if you look in the book, it shows a ball and stick structure where all of the black circles represent carbon, all of the white circles are hydrogen, and the one reddish -brown sphere is bromine.
00:20
So if you transpose that from the ball and stick structure to a line angle structure, this is the product.
00:27
This is your two bromopentine.
00:33
Now, the question asks you to figure out two possible starting alkenes that would result in this product.
00:44
So basically what you want to do is you remember you have an addition reaction, so an addition reaction between hydrobromine plus an alken is going to form a bromalcane.
01:02
And you form this by, let's say you have some r group and r group, you're going to have still this r group, but you're going to have a hydrogen on one carbon and a bromine on the other carbon.
01:23
So if we look at our two bromopentane, we have a bromine on this carbon, and we have a hydrogen on this carbon and also a hydrogen on this carbon.
01:38
So we can think about our two starting alkenes.
01:45
If we think that this carbon -carbon bond was initially an alken...