Question

The following C function takes a singly linked list as an input argument. It modifies the list by moving the last element to the front of the list and returns the modified list. Some part of the code is left blank. ``` typedef struct node I int value; struct node * next? 1 Node; Node move_to_front (Node head) i Node 'p, 'q; If({lead = = nuLL || (head->next = = NULL)) return heads q = NuLl; ; p = head; while {p-> next !=NULL) ! q=p; p=p->next, return head; l ``` Choose the correct alternative to replace the blank line A. $\mathrm{q}=$ NULL; $\mathrm{p}->$ next $=$ head; head $=\mathrm{p}$; B. $q$->next $=$ NULL; head = p; p->next $=$ head; C. head = p; p->next = q; q->next = NULL; D. $q$->next = NULL; $p$->next = head; head = p

    The following C function takes a singly linked list as an input argument. It modifies the list by moving the last element to the front of the list and returns the modified list. Some part of the code is left blank.
```
typedef struct node I
    int value;
    struct node * next?
    1 Node;
Node *move_to_front (Node *head)
i
    Node 'p, 'q;
        If({lead = = nuLL || (head->next = = NULL))
            return heads
        q = NuLl; ; p = head;
        while {p-> next !=NULL) !
            q=p;
            p=p->next,
        return head;
l
```

Choose the correct alternative to replace the blank line
A. $\mathrm{q}=$ NULL; $\mathrm{p}->$ next $=$ head; head $=\mathrm{p}$;
B. $q$->next $=$ NULL; head = p; p->next $=$ head;
C. head = p; p->next = q; q->next = NULL;
D. $q$->next = NULL; $p$->next = head; head = p

Data Structures Using C

Amol M. Jagtap, Ajit… 1st Edition

Chapter 4, Problem 2

Instant Answer

Step 1

It takes a singly linked list and moves the last element to the front of the list. Step 2: Let's analyze the given code: - The function first checks if the list is empty or has only one element. In either case, it returns the list as is. - Then it initializes two Show more…

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The following C function takes a singly linked list as an input argument. It modifies the list by moving the last element to the front of the list and returns the modified list. Some part of the code is left blank. ``` typedef struct node I int value; struct node * next? 1 Node; Node *move_to_front (Node *head) i Node 'p, 'q; If({lead = = nuLL || (head->next = = NULL)) return heads q = NuLl; ; p = head; while {p-> next !=NULL) ! q=p; p=p->next, return head; l ``` Choose the correct alternative to replace the blank line A. $\mathrm{q}=$ NULL; $\mathrm{p}->$ next $=$ head; head $=\mathrm{p}$; B. $q$->next $=$ NULL; head = p; p->next $=$ head; C. head = p; p->next = q; q->next = NULL; D. $q$->next = NULL; $p$->next = head; head = p

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