00:01
So in this problem, we're supposed to basically at the very end come up with a p value to, or a p value to calculate the significance and see if the means for these three treatment groups are equal.
00:16
And what this problem does really well is basically give you a step by step for how you should approach anova problems altogether.
00:22
So at the very end, we're supposed to create an nova table, which is this thing.
00:26
And this anova table will basically give you all the information.
00:30
You need in order to conduct this hypothesis test at the very end.
00:34
But in between, we need to come up with some values.
00:37
So here i have the given information in the problem.
00:41
The mean for the treatment group a is 156.
00:45
The mean for the treatment group b is 142.
00:47
And the mean for the treatment group c is 134.
00:50
Then the variance for the treatment group a is 164 .4.
00:54
Variance for the treatment group b is 131 .2.
00:57
And the variance for the treatment group c is 110 .4.
01:01
So the first thing the question asks us to do is find the sum of squares between treatments.
01:06
And the sum of squares between treatments is also known as the, or the first thing we need to find in order to calculate a sum of squares between treatments is what we call the grand mean, which is denoted by x double bar.
01:21
So that is just the sample mean of a minus plus the sample mean of b plus the sample mean of c all over the number of treatment groups, which we will call n.
01:38
Okay, so in this situation, it will be 156 plus 142 plus 134 over 3, which is equal to 144.
01:50
So this is our grand mean.
01:53
This value comes up a lot in in our innova tests or in our calculations for an an annova.
01:59
And now to actually calculate the sum of squares between treatments, we will take the sum, the sum from j equals 1 to k, where j is just a holder value, and k is the number of treatments.
02:22
I know we already used n.
02:23
Actually, let me just use n.
02:25
So n is the number of treatments.
02:26
J equals 1 to end the number of treatments.
02:30
And here i have k subj, where k is the number of elements, number of elements in each treatment, each treatment population, times the mean of each treatment minus the grand mean squared.
02:54
So, in this situation, this is equal to 6 times 156 minus 144 squared plus 6 times 142 minus 144 squared plus 6 times 134 minus 144 squared.
03:15
Sorry, that last part's just squeezed in there.
03:19
But this is equal to 14888.
03:24
This is our final value for sum of squares between treatments.
03:29
So i'm going to go ahead and add that to our anova table.
03:33
The sum of squares between treatments is 1488.
03:39
And now we are going to use this value to calculate a mean square between treatments.
03:43
The mean square between treatments is simply the sum of squares between treatments over the number of elements, n minus 1.
03:58
So we calculated the sum of squares between the treatments to be 1488, 1 ,488 over the number of treatments, and we have three treatment populations, a, b, and c.
04:16
So that is 3 minus 1, which is 2.
04:21
So this is equal to 744, 744.
04:28
This is the mean square between our treatment.
04:30
So let me go ahead and update this table.
04:33
So the mean square between our treatments is 744...