00:01
So in this question, we need to find the rate of formation and decomposition of the reactants and products for the reaction of psychobutane to form ethylene.
00:19
So we're given the data as time and minutes and malarity of the reactant.
00:28
So for this problem, we need to change the time to seconds because we're.
00:34
Trying to find the rates of formation and decomposition at time is equal to 1 ,000 second and 9 ,000 seconds.
00:43
You can see from the balanced chemical reaction, one mole of reaction gives two moles of product.
00:48
So for every one mole of reacting use up, two moles of product are formed.
00:52
The rate of formation of a product is therefore going to be twice the rate of decomposition of the reactant.
01:01
So if we find the rate of decomposition, we can find the rate of formation.
01:06
So here is the graph, if we just graph the data based off of the time in seconds or the time in minutes.
01:21
So here i've already converted the x -axis to seconds, but if you graph it in minutes, it should look similar.
01:31
And how i got the graph for the product was that since you know that one mole of reacting gives two moles of the product, we're going to, at each time, subtract the molarity of the reactant from the initial molarity, and this difference is going to multiply by two, and that's going to give you the molarity of the product.
02:01
Because basically, for example, at time is equal to 4 ,000 minutes, we're going to take the initial molarity of c4h8, and we're going to subtract the molarity at that time.
02:17
And then the difference needs to be multiplied by two because for every one mole of reactant, we get two moles of products, and then that is going to equal the molarity of the product that is formed at time is equal to 4 ,000 minutes.
02:35
So then we can just convert time from minutes to seconds by multiplying by 60.
02:48
And that changes our units on the x -axis.
02:51
So you can see that this is a bit crowded...