Question
The following data were obtained for the reaction of $\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CBr}$ with hydroxide ion at $55^{\circ} \mathrm{C}$. $\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CBr}+\mathrm{OH} \longrightarrow\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}+\mathrm{Br}$ What is the rate law for the reaction? What is the value ofthe rate constant (with correct units) at this temperature?
Step 1
To do this, we can compare the first two experiments where the concentration of hydroxide ion is kept constant. We can write the rate law for these two experiments as follows: Rate$_1$ = k[$\left(\mathrm{CH}_{3}\right)_{3} Show more…
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The following data were obtained for the reaction of $\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CBr}$ with hydroxide ion at $55^{\circ} \mathrm{C}$. $\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CBr}+\mathrm{OH}^{-} \longrightarrow\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}+\mathrm{Br}^{-}$ What is the rate law for the reaction? What is the value of the rate constant (with correct units) at this temperature?
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